A mixture of reactants and products for the reaction shown below is at equilibrium in a 5.0 L container. What would most likely happen to the
equilibrium if the volume of the container were reduced to 3.0 L?
N (9) + 3H2(9)
A2NH,
TH (9)
A. The concentrations of N2, H2, and NH3 would decrease until
equilibrium was reached again.
B. More N2, H2, and NH3 would be produced until a new equilibrium
position was reached.
C. More NH3 would be produced until a new equilibrium position was
reached.
D. More Ny and H2 would be produced until a new equilibrium
position was reached.

b) mutualism

hope this : )

give me abc and i will get it for u.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2