Se tiene 300 ml de una solución a pH 3,6 constituido por 0,012 mol de acido debil (Ka= 4,5 x 10-4) y 0,023 mol de base o sal conjugada. Si se le agrega 0,12 mol de un ácido fuerte, su valor de pH es:

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The reaction 2kalsi3o8 + 2(h+ + hco3-) + h2o  →  al2si2o5(oh)4 + 2k+ + 2hco3- + 4sio2 shows that feldspar kalsi3o8 is chemically altered by hydrolysis to form chalky-looking clay mineral kaolinite al2si2o5(oh)4. the chemical breakdown of potassium feldspar due to exposure to acidic water results to the mineral binding with the water molecule to become kaolinite with silica and potassium and bicarbonate ions in solution.

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