Multiply each half reaction by the correct number, in order to balance charges for the two half reactions. Mg--> mg2++2c Au++e--> Au Please i need the answer quick i couldnt find it anywhere on the web

Mg(s) + 2Ag^+(aq) >Mg^2+(aq) + 2Ag(s)

Explanation:

The key to balancing redox reaction equations is this; ensure that the number of electrons lost in the oxidation half reaction equation is equal to the number of electrons gained in the reduction half reaction equation. The both half reaction equations can now be combined to give the overall reaction equation.

For the redox reaction under consideration;

Oxidation half equation;

Mg(s) > Mg^2+(aq) + 2e

Reduction half equation;

2Ag^+(aq) +2e > 2Ag(s)

Overall balanced redox reaction equation;

Mg(s) + 2Ag^+(aq) >Mg^2+(aq) + 2Ag(s)

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first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j