Calculate the number of milliliters of 0.656 M KOH required to precipitate all of the Co2 ions in 187 mL of 0.745 M Co(NO3)2 solution as Co(OH)2. The equation for the reaction is:

THE MILLILITERS OF 0.656 M KOH REQUIRED TO PRECIPITATE ALL THE Co2 IONS IN 187 mL OF 0.745 M Co(NO3)2 SOLUTION IS 212.37 mL

EQUATION FOR THE REACTION IS :

2 KOH + Co(NO3)2 > Co(OH)2 + 2 KNO3

Explanation:

Using dilution formula:

M1V1 = M2V2

V2 = M1 V1 / M2

M1 = 0.745 M

V1 = 187 mL

M2 = 0.656 M

V2 = unknown

V2 = 0.745 * 187 / 0.656

V2 = 139.315 / 0.656

V2 = 212.37 mL

the number of milliliters of 0.656 M KOH required to precipitate all of the Co 2 ions is 212.37 mL.

The equation for the reaction is:

2KOH + Co(NO3)2 > Co(OH)2 + 2KNO3

That is 2 moles of potassium hydroxide react with 1 mole of cobalt(11) nitrate to form 1 mole of cobalt hydroxide and 2 moles of potassium nitrate

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