Chemistry question. Image attached.

The balanced equation is given below: C2H6O + 3O2 —> 2CO2 + 3H2O

The coefficients are: 1, 3, 2, 3

Explanation:

C2H6O + O2 —> CO2 + H2O

The above equation can be balance as follow:

There are 2 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 2 in front of CO2 as shown below:

C2H6O + O2 —> 2CO2 + H2O

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

C2H6O + O2 —> 2CO2 + 3H2O

There are a total of 3 atoms of O on the left side and a total of 7 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:

C2H6O + 3O2 —> 2CO2 + 3H2O

Now the equation is balanced.

The coefficients are: 1, 3, 2, 3.

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.