an extra strength antacid tablet contains 750 mg of active ingredient, caco3. if it takes 22.25 ml of hcl to neutralize the tablet, how strong is the acid

The HCl is very strong since its pH is equal to 0.17.

Explanation:

The reaction between CaCO₃ and HCl is:

CaCO₃(s) + 2HCl(aq) ⇄ CaCl₂(aq) + CO₂(g) + H₂O(l)     (1)    

The number of moles of CaCO₃ is:

Where:

m: is the mass = 0.750 g

M: is the molar mass = 100.0869 g/mol

From the reaction (1) we have that 1 mol of CaCO₃ reacts with 2 moles of HCl, so the number of moles of HCl is:  

Now, with the number of moles of HCl we can find its concentration:

Finally, the pH of the acid is:

The pH obtained is very low, so the HCl is very strong.

Therefore, the HCl is very strong since its pH is equal to 0.17.

I hope it helps you!  

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

personal, she chose to do it.