How many molecules of H2S are required to form 79.0 g of sulfur according to the following reaction? Assume excess SO2.
2 H2S(g) + SO2(g) ? 3 S(s) + 2H2O(l)
9.89 × 1023 molecules H2S
5.06 × 1025 molecules H2S
2.44 × 1023 molecules H2S
1.48 × 1024 molecules H2S
3.17 × 1025 molecules H2S
Answers: 1
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Asample of hydrated tin (ii) chloride (sncl2) has a mass of 4.90 g. when it is dehydrated, it has a mass of 4.10 g. which is the correct chemical formula for the hydrate? sncl2•2h2o sncl2•4h2o sncl2•6h2o
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How many molecules of H2S are required to form 79.0 g of sulfur according to the following reaction?...
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