Chemistry, 15.07.2020 01:01 cornpops4037
The average human body contains 5.00 L of blood with a Fe2+ concentration of 1.10×10−5 M . If a person ingests 9.00 mL of 21.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
Answers: 3
%
ingested is mathematically evaluated as 
![Fe^{2+} + 6 CN^{-} \to [Fe(CN)_6]^{2-}](/tpl/images/0706/5120/f86b8.png)
of 
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The average human body contains 5.00 L of blood with a Fe2+ concentration of 1.10×10−5 M . If a pers...
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