What is the density of iron if it crystallizes in a body-centered cubic unit cell with an edge length of 287 pm

Answer

Density = 7.87g/cm^3

Explanation:

Density is the ratio of mass of the given object to the volume of the object, in this question iron is the given object, then we make use of atomic number of iron

Given:

Length= 287pm = 287*10^-10cm

Atomic mass of Fe= 56.0u

Z=2(for body centered cubic unit cell)

Avogadro number (N 0)=6.022× 10^23

Density= ZM/a^3 × N

Where

Z= body centered cubic unit cell

Then substitute

N= Avogadro's number

a=Length

Density = (2× 56)/(287*10^-10cm)^3 × (6.022 × 10^23)

Density = 7.87g/cm^3

a electronegativity decreases beacuse the size of nucleus is bigger.