What is the pH of 1.00 L of a buffer that is 0.110 M nitrous acid (HNO2) and 0.200 M NaNO2? (pKa of HNO2 = 3.40)

pH = 3.65    

Explanation:

given data

pKa of HNO2 = 3.40

nitrous acid (HNO2) = 0.110 M

NaNO2 = 0.200 M

to find out

What is the pH

solution

we get here ph for acidic buffer  that is express as

pH = pKa + log(salt÷acid)      1

put here value and we get

pH = 3.40 + log(0.200÷0.110)

pH = 3.65    

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