If a solute in water has a concentration of 0.12 mg/mL and has a concentration in ether of 0.60 mg/mL, what is the distribution coefficient, K, between ether and water

K = 5

Explanation:

Distribution coefficient, K, is defined as the ratio between the concentration of a solute in two inmiscible solvents.

K = Concentration in solvent 1 / Concentration in solvent 2

Usually solvent 2 is water.

Replacing with the concentrations in the problem:

K = Concentration in ether / Concentration in water

K = 0.60mg/mL / 0.12mg/mL

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

2b2t

explanation:

2b2t