How much energy is required to vaporize 1.5 KG of aluminum

The amount of energy required to vaporize 1.5 kg of aluminium is 16.345 GJ

Explanation:

Given that the heat of vaporization of aluminium, ΔHvap = 294000 kJ/mol

Mass of the given aluminium = 1.5 kG = 1500 g

Number of moles of aluminium = Mass of aluminium/(Molar Mass of aluminium)

Molar Mass of aluminium = 26.98 g/mol

Therefore, we have;

Number of moles = 1500/26.98 = 55.6 moles

The energy required = The heat of vaporization of aluminium × Number of moles of aluminium

The energy required = 294000 × 55.6 = 16345441.0675 kJ = 16.345 GJ.

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