A sample of oxygen, at 25°C, occupies a volume of 4.24 × 102 milliliters (mL) at 1.36 atm pressure. What pressure must be applied to compress the gas to a volume of 1.91 × 102 mL, with no temperature change?

3.02 atm

Explanation:

Step 1: Given data

Step 2: Find the final pressure

Since the temperature is constant, we can find the final pressure using Boyle's law.

the answer would be a

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :