A Multicomponent organic reaction is HACO + HCOOH + HCN --> HgCBON
There are three reagents in this reaction. If you have 30.7 grams of H2C0, 46.0 grams of HCOOH,
and 24.1 grams of HCN, which would be the limiting reagent? (hint: this is not different from when
you have only two reactants you just need to check for all three)
H2CO
CHCOOH
H5C303N.
CHCN
None of the reagents is limiting

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2