How many moles of AlF3 are present if a scientist isolates 1.28 x 10^27 molecules of AlF3? Show your work in the space below 4.00 moles

2,126 moles

0.00341 moles

2.00 moles

The answer is 2,126 moles

To find the number of moles we use the formula;

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.023 × 10^23

n = N / L

N = 1.28 x 10^27 molecules

n = 1.28 x 10^27 / 6.023 × 10^23

n =2126.245

n = 2,126moles

Hope this helps

2b2t

explanation:

2b2t