Chemistry, 03.07.2020 22:01 kmsg2000

The reaction of nitrogen gas and oxygen gas to form nitrogen monoxide gas is shown below. If the measured concentrations of all three chemicals at some point in time are: [N2] = 0.80 M [O2] = 0.050 M

[NO] = 0.10 M

Which statement is TRUE about the reaction at this point in time? N2(g) + O2(g) ⇄ 2 NO(g) K = 0.10

The reaction is at equilibrium.

The reverse reaction is occurring at a faster rate than the forward reaction.

The forward reaction is occurring at a faster rate than the reverse reaction.

This set of concentration values is impossible because the concentrations of N2 and O2 must be the same.

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Answer from: dlatricewilcoxp0tsdw

The reverse reaction is occurring at a faster rate than the forward reaction.

Explanation:

When the reaction:

aA + bB ⇔ cC + dD

has not reached the balance, it is possible to calculate:

$Qc=\frac{[C]^{c}*[D]^{d} }{[A]^{a}*[B]^{b} }$

where Q is called the reaction quotient, and the concentrations expressed in it are not the equilibrium concentrations, but other concentrations given at a time of the reaction.

Comparing Qc with Kc allows to find out the status and evolution of the system:

If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium. If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration. If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

In the case of the reaction:

N₂ (g) + O₂ (g) ⇄ 2 NO (g)

$Qc=\frac{[NO]^{2} }{[N_{2} ]*[O_{2} ] }$

Being:

[N₂] = 0.80 M [O₂] = 0.050 M [NO] = 0.10 M

and replacing:

$Qc=\frac{0.10^{2} }{0.80*0.050 }$

you get:

Qc= 0.25

Being Kc=0.10, Qc>Kc. Then the system is not in equilibrium and will evolve to the left to increase the concentration of reagents. So, the reverse reaction is occurring at a faster rate than the forward reaction.

Answer from: Quest

quartz

explanation:

Which of these is not a commonly mined metallic substance?

Answer from: Quest

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

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The reaction of nitrogen gas and oxygen gas to form nitrogen monoxide gas is shown below. If the mea...