Arrange the compounds in order of decreasing solubility in water. a) 1-butanthiol b) 1-butanol c) 1,2-propanediol Answer by ordering the letters a-c as a string, e. g. acb, starting with the compound of highest solubility. The order of decreasing solubility is

cba

Explanation:

Alcohols are soluble in water because of the presence of the -OH group which interacts with water by hydrogen bonding leading to the miscibility of low molecular weight alcohols with water.

The solubility of alcohols in water decreases as the length of the alkyl chain increases. Similarly, the more the number of -OH groups present, the greater the solubility bof the alcohol in water.

1-butanol contains less -OH groups than 1,2-propanediol as well as a longer alkyl chain hence 1-butanol is less soluble in water than 1,2-propanediol. Butanthiol has the least solubility in water because the -SH group forms weaker hydrogen bonds than the -OH group.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

it is stable as it is in group 0 which have full outer shells of electrons