When copper is heated with an excess of sulfur, copper(I) sulfide is formed. In a given experiment, 0.0970 moles of copper was heated with excess sulfur to yield 1.76 g copper(I) sulfide. What is the percent yield?

The percentage yield of the experiment obtained by the reaction of 0.0970 mole of copper with excess sulfurs is 22.8%

We'll begin by calculating the number of mole of Cu₂S produced from the reaction. This can be obtained as follow:

2Cu + S —> Cu₂S

From the balanced equation above,

2 moles of Cu reacted to produce 1 mole of Cu₂S.

Therefore,

0.0970 mole of Cu will react to produce = = 0.0485 mole of Cu₂S.

Next, we shall determine the theoretical yield by calculating the mass of 0.0485 mole of Cu₂S.

Molar mass of Cu₂S = (63.5×2) + 32 = 159 g/mol

Mole of Cu₂S = 0.0485 mole

Mass = mole × molar mass

Mass of Cu₂S = 0.0485 × 159

Thus, the theoretical yield of Cu₂S is 7.7115 g

Finally, we shall determine the percentage yield of Cu₂S.

Actual yield = 1.76 g

Theoretical yield = 7.7115 g

Therefore, the percentage yield of the experiment is 22.8%

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Percent yield = 22.8 %

Explanation:

Step 1: Data given

Numbers of moles  copper = 0.0970 moles

Mass of copper(I) sulfide = 1.76 grams

Step 2: The balanced equation

2Cu + S ⇒ Cu2S

Step 3:  Calculate moles of Cu2S

For 2 moles Cu we need 1 mol S to produce 1 mol Cu2S

For 0.0970 moles Cu we'll hace 0.0970 / 2 = 0.0485 moles

Step 4: Calculate mass of Cu2S

Mass Cu2s = moles Cu2S * molar mass Cu2S

Mass Cu2S = 0.0485 moles * 159.16 g/mol

Mass Cu2S = 7.72 grams

Step 5: Calculate percent yield

Percent yield = (actual yield/ theoretical mass) * 100%

Percent yield = (1.76 grams / 7.72 grams)*100%

Percent yield = 22.8 %

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

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