zinc metal and hydrochloric acid react together according to the following equation 2HCl (aq)+ Zn(s) = ZnCl2(aq) +H2(g) if 5.98 g Zn reacts with excess HCl at 298 K and 0.978 atm what volume of H2 can be collected

2.29 L

Explanation:

In this question we have to start with the chemical reaction:

The reaction is already balanced. So, if we have an excess of HCl the compound that would limit the production of would be Zn. So, we have to follow a few steps:

1) Convert from grams to moles (Using the atomic mass of Zn 65.38 g/mol).

2) Convert from moles of Zn to moles of (Using the molar mass 1 mol = 1 mol Zn).

3) Convert from mol of to volume (Using the ideal gas equation PV=nRT).

First step:

Second step:

Third step:

We have to remember that R = 0.082 , so:

I hope it helps!

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