Muriatic acid, an industrial grade of concentrated HCl, is used to clean masonry and cement. Its concentration is 11.7 M. For routine use, a diluted solution of 3.50 M is prepared. How many milliliters of 3.50 M muriatic acid solution contain 79.9 g of HCl?

625.4mL

Explanation:

Hello,

To solve this question, we can use "mole concept" which is a method whereby you use the relationship between mole, volume, mass etc to solve to unknown parameters.

From the question,

3.50M = standardized solution

3.50 mole = 1L

1 mole = xL

x = (1 × 1) / 3.50

x = 0.2857L

But 1 mole = molar mass

Molar mass of HCl = 1 + 35.5 = 36.5g/ mol

Relating the molar mass to the volume, I.e 36.5g is present in 0.2857L

36.5g = 0.2857L

79.9g = yL

y = (79.9 × 0.2857) / 36.5

y = 22.82743 / 36.5

y = 0.6254L

Converting 0.6254L to mL = 0.6254 × 1000 = 625.4mL

Therefore, 79.9g of HCl is present in 3.50M of muriatic solution.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8