A 650.0 mL solution contains 125 grams of glucose (C6H12O6). If the molar mass of C6H12O6 is 180.16 g/mol, what is the molarity of this solution? answer options are 0.0106 M C6H12O6 0.0195 M C6H12O6 1.07 M C6H12O6 1.92 M C6H12O6 need help ASAP
will mark brainlest

1.07M

Explanation:

Si tenemos 125g de glucosa, debemos obtener los moles dividiendo esos 125 g por el peso de la glucosa:

mol de glucosa

despues debemos convertir los 650 ml de soln en litros lo cual dividimos entre 1000

de la formula de Molaridad

lol idk man i guess u gotta ask bill nye the science guy

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol