What volume of CO2 forms when 8.00 L of hexane burn, assuming the two volumes are measured under the same conditions? What volume of oxygen will be needed? pls help asap

48.00L of CO₂ are formed.

76.00L of O₂ are needed

Explanation:

Based on the reaction:

C₆H₁₄ + 19/2O₂ → 6CO₂ + 7H₂O

Where 1 mole of hexane reacts with 19/2 of O₂ to produce 6 moles of CO₂ and 7 moles of H₂O

Using Avogadro's law, volume is directely proportional to moles of gas.

If 1 mole of reaction of hexane is equal to 8.00L, 6 moles of CO₂ that are produced have as volume:

8.00L ₓ 6 =

Again, for a complete burning of hexane, you need 19/2 times of moles of oxygen. As you have 8.00L of hexane, you need:

8.00L × (19/2) =

i believe the answer is 5,000