Calcium carbonate, when heated, forms calcium oxide and carbon dioxide. 100grams of calcium carbonate will produce 56grams of calcium oxide. How many grams of carbon dioxide will it produce? Show working out

It will produce 44 grams of carbon dioxide

Explanation:

Step 1: Data given

MAss of CaCO3 = 100 grams

Molar mass of CaCO3 = 100.09 g/mol

Mass of CaO produced = 56 grams

Molar mass of CaO = 56.08 g/mol

Step 2: The balanced equation

CaCO3 → CaO + CO2

Step 3: Calculate moles CaCO3

Moles CaCO3 = mass CaCO3 / molar mass CaCO3

Moles CaCO3 = 100 grams / 100.09 g/mol

Moles CaCO3 = 1.00 moles

Step 4: Calculate moles CaO

Moles CaO = 56 grams / 56.08 g/mol

Moles CaO = 1.00 moles

Step 5: Calculate moles CO2

For 1 mol CaCO3 we'll have 1 mol 1 mol CaO and 1 mol CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 1.00 moles * 44.0 g/mol

Mass CO2 = 44 grams

It will produce 44 grams of carbon dioxide

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

14,16 18 reacts with group