What is the product of the unbalanced combustion reaction below? C4H10(9) + O2(g) →
The Periodic Table
A. C6H1206(s)
B. C(s) + H20(9)
C. CO2(g) + H20(9)
D. CO2(g) + H2(9)

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

16

explanation:

the marks go by 4s