Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is: 2 AlBr3() 2 Al(s) + 3 Br2(1)
We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K. the equilibrium constant for the reaction above.
1) 2 Al(s) + 3 Br2 = 2 AlBrz(s)
2) Al(s) + 3/2 Br2(1) AlBr3(s) K2 =
3) AlBrz(s) = Al(s) + 3/2 Br2(1) K3 =
Drag and drop your selection from the following list to complete the || (1K)12 x 12 1/K Consider the reaction: S(s) + O2(g) SO2(g) Write the equilibrium constant for this reaction in terms of the equilibrium constants, K, and Kb for reactions a and b below:
a) 2 S(s) + 3 O2(g)
b) SO2(g) + 1/2O2(g) = 2 SO3(9) Ka SO3(9) Kb K=
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Chemistry, 22.06.2019 01:40, janelisse199820
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The scheme below is from a series of reactions that are part of a synthesis of vitamin a. answer the following questions with reference to this scheme. (i) what is "reagent a"? (ii) draw a step-by-step mechanism which explains the formation of compound c from compound b (iii) which reagents would you use to form compound e from compounds c and d (reagents b and c)? for each reagent suggested above in (ii) explain the role of the reagent in the reaction to (iv) form compound e. you may wish to do this by drawing a mechanism. 1. addition of reagent a но reagent a 2. н, о" thо oh нон-с compound a. compound b. compound c .ch-оh 1. reagent b "сно 2. reagent c сh oh compound e. compound d.
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Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One...
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