__C7H16+ ___O2=
CO2 + H20 how to balance this equation

C7H16 + 11O2 = 7CO2 + 8H2O

Explanation:

Start by balancing the C and H in C7H16 by adding the coefficient of 7 for CO2 because there are 7 C's in C7H16. Similarly, since there are 16 H's in C7H16, balance it by adding the coefficient of 8 to the H2O, which will result in 16 H's.

Finally, add up the O's on the right side and balance it by adding the appropriate coefficient on the O2. On the right, there are 22 O's, so balance the equation by adding the coefficient of 11 on the left for the O2.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.