what is the compound name for the ION SbBO3. Also can someone please tell me what the difference is between just a regular molecule and a ion. And how it changes formulas? Thank you so much!

Antimony Borate

Explanation:

The compound name for the ion SbBO3

That would be Antimony borate

Initially we have the combination of antimony and the borate ion

Antimony has the ion Sb3+ while the borate have the ion BO3(3-)

According to IUPAC naming rules, the 3 on both ions will cancel out during combination to form a single molecule.

The difference between just a regular molecule and an ion is that while a molecule does not carry charge, an ion is charged. The positive or negative charge on an ion is what makes it different from a molecule which is not charged. Also, there must be a combination of a positive and a negative ion before we can have the formation of a molecule

Now, how it changes formula?

Although there are extensive rules but basically, a molecule is formed if there is a combination of ions.

Now, how an ion changes form in a molecule depends on the charge on the other ion

A positive ion most times come in contact with a negative ion to form a molecule.

Now, if we have the same magnitude of charge in both positive and negative sides, the charges will cancel out.

This is in the case of Antimony Borate where we had a magnitude of 3 on the positive and negative sides.

So they cancel out

In a case where this is not the case such as in the case of calcium and borate ion,

We have Calcium as Ca2+ and the borate ion as BO3(3-)

What happens here is that they switch ions and we have;

Ca3(BO3)2

Hope these helps!

Thank you

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml