What is the concentration of a CaBr2 solution if 125.00 g of solute was dissolved in enough water to form 250. ml of solution?

Concentration can be defined in terms of molarity. The molarity has been the moles of solute present in a liter of solution.

Moles of can be calculated as:

Moles =

Molecular weight of = 199.89 g/mol

Moles of   =

Moles of = 0.625 mol.

Volume of solution = 250 ml

1000 ml  = 1 L

250 ml = 0.25 L

Molarity =

Molarity =

Molarity = 2.50 M.

The concentration of 125 grams, 250 ml solution has been 2.50 M.

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2.50M

Explanation:

Concentration of a solution describes how much of a solute is dissolved in a solvent in a solution. Molarity of a solution is one way to calculate the concentration of a solution.

The Molarity, M is calculated using the formula: number of moles (n) / volume of solution (litres).

To calculate, the number of moles (n), we say that number of moles = mass of solute / molar mass

In this case, CaBr2 (Calcium Bromide) solution is used where mass no of Calcium (Ca) is 40g/mol and Bromine (Br) is 79.9g/mol

Molar mass of CaBr2= 40 + 79.9(2)

40 + 159.8 = 199.8

Hence, molar mass of CaBr2 is 199.8g/mol

Mass of solute= 125grams

Number of moles (n) of CaBr2 = 125/199.8 = 0.6256

n = 0.6256moles

Volume of CaBr2 solution is 250millilitres(ml). Since, 1000ml= 1L, then 250ml is 250/1000 L

= 0.25L

Molarity of solution (M) = number of moles (n)/ volume of solution (litres)

M = 0.6256/0.25

M= 2.5

Thus, the molarity (concentration) of the solution is 2.5M

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation: