What is the atomic weight of an element if 4 grams of it contains 2.98 x 10^22 atoms?

N=amount  in moles
N=amount in numbers=2.98x10^22
L=Avagadro's constant=mole-1(6.022x10^23)
m= mass in grams
M=molar mass in g/mol
Now,
n=N/L
  =2.98x10^22/6.022x10^23
  =0.0495 mol ≈0.05 mol
Then,
M=m/n
   =4/0.05
   =80 g/mol
The element is Br

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