Calculate the percent composition of muscovite mica. Its chemical formula is (KF)2(Al2O3)3(SiO2)6(H2O)

Explanation:

(KF)2(Al2O3)3(SiO2)6(H2O)

molecular formula

K₂F₂Al₆Si₆O₂₂H₂

2 x 39 + 2 x 19 + 6 x 27 + 6 x 28 + 22 x 16 + 2 x 2

=  78 + 38 + 162+ 168+ 352+ 4

= 802

Percentage of K = 78 x 100 / 802

= 9.72 %

Percentage of F = 38 x 100 / 802

= 4.74 %

Percentage of Al = 162 x 100 / 802

= 20.2  %

Percentage of Si = 168 x 100 / 802

= 20.9  %

Percentage of O = 352 x 100 / 802

= 43.9 %

Percentage of H = 4 x 100 / 802

= .54  %

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it would be a gas formation