Chemistry, 16.06.2020 23:57 joannamarquez0701

A student has two solutions of a substance. Solution-1: 25M, 400mL, and Solution-2: 30M, 300 ml. What is the molarity of the final solutions if these two solutions are mixed?

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Answer from: JaySavage7001

The molarity of the final solutions if these two solutions are mixed is 27.14 $\frac{moles}{L}$

Explanation:

Yo know:

Solution-1: 25M, 400mLSolution-2: 30M, 300 mL

Molarity being the number of moles of solute per liter of solution, expressed by:

$Molarity (M)= \frac{number of moles}{volume}$

You can determine the number of moles that are mixed from each solution as:

Number of moles= Molarity*Volume

So, being 1 L=1000 mL, for each solution you get:

Solution-1: being 0.400 L=400 mL ⇒ 25 M* 0.400 L= 10 molesSolution-2: being 0.300 L=300 mL ⇒ 30 M* 0.300 L= 9 moles

When mixing both solutions, it is obtained that the volume is the sum of both solutions:

Total volume= volume solution-1 + volume solution-2

and the number of total moles will be the sum of the moles of solution-1 and solution-2:

Total moles= moles of solution-1 + moles of solution-2

So the molarity of the final solution is:

$Molarity (M)= \frac{moles of solution 1 + moles of solution 2}{Volume solution 1 + Volume solution 2}$

In this case, you have:

moles of solution-1: 10 molesmoles of solution-2: 9 molesvolume solution-1: 0.400 Lvolume solution-2: 0.300 L

Replacing:

$Molarity (M)=\frac{10 moles + 9 moles}{0.400 L + 0.300 L}$

Solving:

$Molarity (M)=\frac{19 moles}{0.700 L}$

Molarity= 27.14 $\frac{moles}{L}$

The molarity of the final solutions if these two solutions are mixed is 27.14 $\frac{moles}{L}$

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

i don't know people like to fight everywhere rip.

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A student has two solutions of a substance. Solution-1: 25M, 400mL, and Solution-2: 30M, 300 ml. Wha...