Someone answer please

1) 67.35 H202 x

The H2O2's cancel out, and we have 67.35.

2) Br2+Cl2=2BrCl

3) 2.74 Cl2= 2BrCl/Cl2

Thus, we have 2.74(2) which is 5.48

Explanation:

1) 67.35 H202 x

The H2O2's cancel out, and we have 67.35.

2) Br2+Cl2=2BrCl

3) 2.74 Cl2= 2BrCl/Cl2

Thus, we have 2.74(2) which is 5.48

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole