What is the final volume of a gas that started at 20 L and 50 atm pressure when the pressure is decreased to 14 atm? Answer must be to nearest whole number.

Final volume = 71 L

Explanation:

Since the question involves volume and pressure, we use Boyle's law which states that

P1V1 = P2V2;

Where P1 and P2 are initial and final pressure respectively, and V1 and V2 are initial and final volumes respectively.

P1 =50 atm, P2 = 14 atm, V1 = 20 L, V2 = ?

V2 = P1V1/P2

V2 = (50 * 20)/14

V2 = 71 L

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the answer to this question is 3.