How many moles of potassium hydroxide are needed to completely react with 1.73 moles of aluminum sulfate according to the following equation: Al2(SO4)3 + 6 KOH ---> 2 Al(OH)3 + 3 K2SO4

10.4mol

Explanation:

Step 1: Write the balanced equation

Al₂(SO₄)₃ + 6 KOH ⇒ 2 Al(OH)₃ + 3 K₂SO₄

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of Al₂(SO₄)₃ to KOH is 1:6.

Step 3: Calculate the moles of potassium hydroxide needed to completely react with 1.73 moles of aluminum sulfate

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.