How many moles of gas are contained in a 60.0L cylinder at a pressure of 200.0 atm and a temperature of 25.0? A.(490.48 mol) B.(590.84 mol) C.(340.56 mol) D.(540.67 mol)

A. 490.48mol

Explanation:

Using the ideal gas equation; PV =nRT

where P = Presssure = 200 atm

          V = Volume = 60L

          n = Number of moles

          R = Gas constant = 0.08206 L.atm/mol/K

          T = Temperature = 25 °C  + 273 = 298K

Make "n" the subject of the formular;

n =  PV /  RT

   =  200   x    60   /    0.08206 x  298

   =  490.73  mol, which is closest to  option A. 490.48mol

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