What is the equilibrium constant for the following reaction:HCO2H(aq) + CN–(aq) HCO2–(aq) + HCN(aq)Does the reaction favor the formation of reactants or products? The acid dissociation constant, Ka, for HCO2H is 1.8 x 10–4and the acid dissociation constant for HCN is 4.0 x 10–10.(A) K = 1.00. The reaction favors neither the formation of reactants nor products.(B) K = 2.2 x 10–6. The reaction favors the formation of products.(C) K = 2.2 x 10–6. The reaction favors the formation of reactants.(D) K = 4.5 x 105. The reaction favors the formation of products.(E) K = 4.5 x 105. The reaction favors the formation of reactants.

(D) K = 4.5 x 10⁵. The reaction favors the formation of products

Explanation:

HCOOH + CN⁻ ⇆ HCOO⁻ + HCN

K = [HCOO⁻] [ HCN ] / [ HCOOH] [ CN⁻]

HCOOH ⇄ H ⁺ + COO⁻

K₁ = [ H⁺] [ COO⁻ ] / [HCOOH ]

HCN ⇆ H⁺ + CN⁻

K₂ = [ H⁺] [ CN⁻] / [ HCN ]

K₁ / K₂

= [ H⁺] [ COO⁻ ] / [HCOOH ]  X  [ HCN ] / [ H⁺] [ CN⁻]

= [ COO⁻ ][ HCN ] / [HCOOH ]  [ CN⁻]

= K

K = K₁ / K₂

= 1.8  x 10⁻⁴ / 4 x 10⁻¹⁰

= 4.5 x 10⁵

So equilibrium constant of the reaction

HCOOH + CN⁻ ⇆ HCOO⁻ + HCN

is very high . Hence reaction favours the formation of product.

option (D) is correct.

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.