If a gas at 35°C and 2.3 atm is heated to 50°C, then what will the new pressure be? (Gay Lussac's Law) Remember to convert Celsius tempertature into Kelvin. (Take the Celsius values and add 273)

THE NEW PRESSURE OF THE GAS AT 50 °C IS 2.41 atm.

Explanation:

Initial temperature = 35 °C = 35 + 273 K= 308 K

Final temperature = 50 °C =50 + 273 K = 323 K

Initial pressure = 2.3 atm

Final pressure = unknown

Using the combined gas equation to get the relationship between pressure and temperature for a given gas sample, we have;

P1 / T1 = P2 / T2

P2 = P1 T2 / T1

P2 = 2.3 * 323 / 308

P2 = 742.9 /308

P2 = 2.41 atm.

THE NEW PRESSURE IS 2.41 atm at 50 °C

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.