A 300 gram sample of pure water exerts a vapor pressure of 740 millimeters of mercury on the walls of its container. If 0.4 00 moles of glucose (C6H12O6) is added to the water, what will be the vapor pressure of the resulting solution? 723 mm Hg
738 mm Hg
739 mm Hg
743 mm Hg

The equation,P(solution) = X(solvent * P(solvent), can be used to determine vapor pressure lowering. 300 grams of water is 300g x 1 mole/18.0g = 16.67 moles water. Thus, X = 16.67 moles water/17.07 moles total = 0.977 and the new pressure = 0.977 x 740 mm Hg = 723 mm Hg.

the tides are influenced by both the moon and the sun, it's easy to see that when the sun lines up with the moon and the earth, as during a new moon or full moon, the tidal effect is increased. these are known as spring tides, named not for the season, but for the fact that the water "springs" higher than normal. on the other hand, if the sun and the moon are 90 degrees apart in relation to an observer on earth as during the first quarter moon or third quarter moon, then high tides are not as high as they normally would be. this is because despite its greater distance, the sun's mass allows it to exert enough gravitational force on the oceans that it can negate some of the effects of the moon's pull. this phenomenon of lower high tides is called a neap tide. if you need more information on this topic visit moonconnection.com.