Solve for V2 when P1 = 1.0 atm V1 = 22.4 L and P2 = 4.0 atm
This is a Boyle’s law gas problem

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being