Acompound is 54.53% c, 9.15% h, and 36.32% o. what is its empirical formula?

the molar mass of the compound is 132 amu. what is its molecular formula?

The empirical formula : C₂H₄O

The molecular formula : C₆H₁₂O₃

The empirical formula is the smallest comparison of atoms of compound forming elements.

A molecular formula is a formula that shows the number of atomic elements that make up a compound.

(empirical formula) n = molecular formula

The principle of determining empirical formula and molecular formula

Percentage of elements A and B in AxBy compounds:

% A in AₓBy = (x x Ar A / Mr AₓBy) x% AₓBy

% B in AₓBy = (y x Ar B / Mr AₓBy) x% AₓBy

It is known about the% mass of each element

To find the empirical formula, we look for its mole ratio (% mass/ its relative atomic mass)

C = 54.53 / 12 = 4.544

H = 9.15 / 1 = 9.15

O = 36.32 / 16 = 2.27

To simplify the comparison as an integer, we divide by the mole ratio of the smallest element

C = 4.544 / 2.27 = 2

H = 9.15 / 2.27 = 4

O = 2.27/2.27 = 1

So the empirical formula:

C₂H₄O

We look for the molecular formula to get the number of atoms making up the compound

(C₂H₄O) n = molecular formula

(2.12 + 4.1 + 16) n = 132

(44) n = 132

n = 3

So molecular formula = C₆H₁₂O₃

the molar mass of a substance

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Determine the empirical and molecular formulas

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Determine the molecular formula of the compound

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Keywords: empirical formula, molecular formula, mass, mole

3 1/4 %

explanation: