3. The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. How does the gas pressure change?

The new pressure is 8 times the original pressure.

Explanation:

Data obtained from the question include:

Initial volume (V1) = 4L

Final volume (V2) = 0.5L

Initial pressure (P1) = P

Final pressure (P2) =..?

The new pressure can be obtained by using the Boyle's law as shown below:

P1V1 = P2V2

P x 4 = P2 x 0.5

Divide both side by 0.5

P2 = P x 4 / 0.5

P2 = 8P

Therefore, the new pressure is 8 times the original pressure.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.