The molarity of a solution containing 7.1 g of sodium sulfate in 100 mL of an aqueous solution is

0.50M of solution

Explanation:

Molarity is defined as the ratio between moles of solute (In this case, sodium sulfate, Na₂SO₄) per liter of solution.

Moles of 7.1g of Na₂SO₄ (Molar mass: 142g/mol) are:

7.1g Na₂SO₄ × (1mol / 142g) = 0.05 moles of Na₂SO₄.

In 100mL = 0.100L:

0.05 moles Na₂SO₄ / 0.100L = 0.50M of solution

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