Water forms according to the equation below: 2H2(g) + O2(g) -> 2H2O(g) /\Hrxn = -483.64 kJ

How much energy is released during the formation of 1 mol H2O(g)?

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the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3