What mass of copper is consumed in the reaction with hydrochloric acid if 10.0 g of gas is collected?

317 g

Explanation:

Cu + 2HCl --> CuCl2 +H2

1      :     2           1 : 1

1 mole of Cu  = 63.5 g

1 mole of  H2 = 2g

1 mole  Cu produces = 1 mole of H2

63.5 g of Cu produces = 2 g of H2

So

10 g of H2 will be produced from =  (63.5/2)*10 = 317 g of Copper

there all right good

explanation:

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.