PLEASE HELP WILL MARK BRAINLIEST

5.3 mol Al reacts with 3.0 mol Cl2 to produce Aluminum chloride.

(ANSWER A, B, C and D)

a. Write and balance the chemical equation.

b. Identify the limiting reagent.

c. Calculate the moles of product formed.

d. calculate the number of moles of excess reagent remaining after the

reaction is completed.

a) 2Al + 3Cl2 ⇆ 2AlCl3

b) Cl2 is the limiting reactant.

c)  2.0 moles AlCl3

d) There will remain  3.2 moles Al

Explanation:

Step 1: Data given

Number of moles Al = 5.3 moles

Number of moles Cl2 = 3.0 moles

Step 2: The balanced equation

2Al + 3Cl2 ⇆ 2AlCl3

Step 3: Calculate the limiting reactant

For 2 moles Al we need 3 moles Cl2 to produce 2 moles AlCl3

Cl2 is the limiting reactant. It will completely be consumed. (3.0 moles)

Al is in excess. There will react 2/3 * 3.0 = 2.0 moles

There will remain 5.2 - 2.0 = 3.2 moles

Step 4: Calculate moles AlCl3

For 2 moles Al we need 3 moles Cl2 to produce 2 moles AlCl3

For 3.0 moles Cl2 we'll have 2/3 * 3.0 = 2.0 moles AlCl3

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.