Compute the concentration of HCl for all three trials using the formula molarity = mol / L.

Trial 1 (20.61 mL HCl): M

Trial 2 (20.06 mL HCl): M

Trial 3 (19.67 mL HCl): M

Trial 1 (20.61 mL HCl):  

⇒ 0.121 M

Trial 2 (20.06 mL HCl):  

⇒ 0.125 M

Trial 3 (19.67 mL HCl):  

⇒ 0.122 M

the answer for the next question, Compute the average concentration (molarity) of HCl for all three trials, is 0.123 M.

Explanation: