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Aqueous lead (II) nitrate, Pb(NO3)2 undergoes a double displacement reaction with aqueous sodium chloride, NaCl, in which a precipitate forms. If the precipitate contains lead, write the balanced chemical equation for this reaction. Be sure to include the states of each of the reactants and products.

The balanced chemical equation for the reaction between aqueous lead(II) nitrate (Pb(NO₃)₂) and sodium chloride (NaCl) is:  

Pb(NO₃)₂(aq) + 2NaCl(aq) → PbCl₂(s) + 2NaNO₃(aq)

When Pb(NO₃)₂ reacts with NaCl, the following chemical reaction takes place:

Pb(NO₃)₂(aq) + NaCl(aq) → PbCl₂(s) + NaNO₃(aq) (1)

In this double displacement reaction, lead(II) chloride precipitates and sodium nitrate dissociate in the aqueous solution.  

To balance equation (1), we need to make sure that the number of each element is the same in the reactants and products.  

In equation (1), we have one Cl atom in the reactants and two Cl atoms in the products, so we need to add a coefficient of 2 before the NaCl.

Pb(NO₃)₂(aq) + 2NaCl(aq) → PbCl₂(s) + NaNO₃(aq) (2)  

We can see from equation (2) that there are two Na atoms in the reactants and one Na atom in the products, so we need to add a coefficient of 2 before NaNO₃.

Pb(NO₃)₂(aq) + 2NaCl(aq) → PbCl₂(s) + 2NaNO₃(aq)  (3)  

Equation (3) is balanced now.  

Therefore, the balanced chemical equation is:

Pb(NO₃)₂(aq) + 2NaCl(aq) → PbCl₂(s) + 2NaNO₃(aq)

Learn more about chemical reactions here:

I hope it helps you!

Pb(NO₃)₂ (aq)  +  2 NaCl (aq)  ⇒  PbCl₂ (s)  +  2 NaNO₃ (aq)

Explanation:

To balance an equation, you need to make sure the atoms on one side are equal to the atoms on the other side.

In a double displacement reaction, the reactant switch the atoms they are bonded to.

You can figure out the states by the descriptions.  The two reactants are aqueous.  The product with lead will be solid.  It is implied that the other product will be aqueous.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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i think it's c. i'm not sure but i think so.