Chemistry, 29.05.2020 05:00 Coltong121
One millimole of Ni(NO3)2 dissolves in 240.0 mL of a solution that is 0.500 M in ammonia. The formation constant of Ni(NH3)62+ is 5.5×108. What is the initial concentration of Ni(NO3)2 in the solution? What is the equilibrium concentration of Ni2+(aq ) in the solution?
Answers: 2
![[Ni^{2+}]_0=0.0042M](/tpl/images/0669/8824/46776.png)
![[Ni^{2+}]_{eq}=0M](/tpl/images/0669/8824/028c2.png)
![Ni^{+2}+6NH_3\rightleftharpoons [Ni(NH_3)_6]^{2+}](/tpl/images/0669/8824/85f00.png)
![Kf=\frac{[Ni(NH_3)_6]^{2+}}{[NH_3]^6[Ni^{+2}]}](/tpl/images/0669/8824/f8603.png)
![[Ni^{2+}]_0=\frac{0.001mol}{0.240L} =0.0042M](/tpl/images/0669/8824/ca35e.png)
due to the reaction extent:
![[Ni^{2+}]_{eq}=0.0042M-x=0.0042M-0.0042M=0](/tpl/images/0669/8824/b9bd2.png)
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One millimole of Ni(NO3)2 dissolves in 240.0 mL of a solution that is 0.500 M in ammonia. The format...
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