A certain metal forms a soluble sulfate salt . suppose the left half cell of a galvanic cell apparatus is filled with a solution of and the right half cell with a solution of the same substance. electrodes made of are dipped into both solutions and a voltmeter is connected between them. the temperature of the apparatus is held constant at .

1. Which electride will be positive=right

2. What voltage will the volto meter shows

= 0.020V

Explanation:

We can use the following method to solve the given problem

Concentration of M3+ at anode = 0.450M × 2

Concentration of M3+ at anode= 0.900M

Concentratiom of M3+ at cathode = 4.50M × 2

Concentratiom of M3+ at cathode= 9.00M

M(s) > M3+(aq) + 3e at anode

M3+(aq) (9.00M) + 3e > M(s) at cathode

number of electron transfer is given as n = 3

reaction quotient,Q= [M3+]low/[M3+]high

Q = 0.900M/9.00M

Q = 0.1

Nernst equation for concentration cell at 25℃ is

Ecell = - (0.0592V/n)logQ

Ecell = - (0.0592V/3)log(0.1)

Ecell = 0.020V which is our final answer

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.

i believe the answer is three water molecules