What pressure is exerted by 0.90 moles of gas at 50 C if the gas is in a 1.25 L container?

19.07 atm

Explanation:

Data obtained from the question include the following:

Number of mole (n) = 0.9 mole

Temperature (T) = 50°C = 50°C + 273 = 323K

Volume (V) = 1.25L

Pressure (P) =...?

Note: the gas constant (R) = 0.082atm.L/Kmol

The pressure exerted by the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

P = nRT /V

P= (0.9 x 0.082 x 323)/1.25

P = 19.07 atm

Therefore, the pressure exerted by the gas is 19.07 atm

the correct answer is:

a. formation of precipitation

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.